49x^2-4x^2=180

Solution for 49x^2-4x^2=180 equation:

49x^2-4x^2=180

We move all terms to the left:

49x^2-4x^2-(180)=0

We add all the numbers together, and all the variables

45x^2-180=0

a = 45; b = 0; c = -180;
Δ = b2-4ac
Δ = 02-4·45·(-180)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*45}=\frac{-180}{90}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*45}=\frac{180}{90}
=2
$